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x^2+2.16x-3.24=0
a = 1; b = 2.16; c = -3.24;
Δ = b2-4ac
Δ = 2.162-4·1·(-3.24)
Δ = 17.6256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.16)-\sqrt{17.6256}}{2*1}=\frac{-2.16-\sqrt{17.6256}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.16)+\sqrt{17.6256}}{2*1}=\frac{-2.16+\sqrt{17.6256}}{2} $
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